The original equilibrium E 0 is at the intersection of AD and SRAS 0 . When SRAS shifts right, then the new equilibrium E 1 is at the intersection of AD and SRAS 1 , and then yet another equilibrium, ...The original equilibrium E 0 is at the intersection of AD and SRAS 0 . When SRAS shifts right, then the new equilibrium E 1 is at the intersection of AD and SRAS 1 , and then yet another equilibrium, E 2 , is at the intersection of AD and SRAS 2 . Shifts in SRAS to the right, lead to a greater level of output and to downward pressure on the price level. (b) A higher price for inputs means that at any given price level for outputs, a lower quantity will be produced so aggregate supply will shift…
The original equilibrium E 0 is at the intersection of AD and SRAS 0 . When SRAS shifts right, then the new equilibrium E 1 is at the intersection of AD and SRAS 1 , and then yet another equilibrium, ...The original equilibrium E 0 is at the intersection of AD and SRAS 0 . When SRAS shifts right, then the new equilibrium E 1 is at the intersection of AD and SRAS 1 , and then yet another equilibrium, E 2 , is at the intersection of AD and SRAS 2 . Shifts in SRAS to the right, lead to a greater level of output and to downward pressure on the price level. (b) A higher price for inputs means that at any given price level for outputs, a lower real GDP will be produced so aggregate supply will shift…